Clarify the // operator (fix typo)
This commit is contained in:
1 parent
dcaf701ef6
commit
71941a0d47
2 files changed
+2
-2
No files matched your search
@@ -2391,7 +2391,7 @@ sections:
|
|||||||
The `//` operator produces all the values of its left-hand
|
The `//` operator produces all the values of its left-hand
|
||||||
side that are neither `false` nor `null`, or, if the
|
side that are neither `false` nor `null`, or, if the
|
||||||
left-hand side produces no values other than `false` or
|
left-hand side produces no values other than `false` or
|
||||||
`true`, then `//` produces all the values of its right-hand
|
`null`, then `//` produces all the values of its right-hand
|
||||||
side.
|
side.
|
||||||
|
|
||||||
A filter of the form `a // b` produces all the results of
|
A filter of the form `a // b` produces all the results of
|
||||||
|
|||||||
Generated
+1
-1
@@ -2577,7 +2577,7 @@ jq \'[true, false | not]\'
|
|||||||
.IP "" 0
|
.IP "" 0
|
||||||
.
|
.
|
||||||
.SS "Alternative operator: //"
|
.SS "Alternative operator: //"
|
||||||
The \fB//\fR operator produces all the values of its left\-hand side that are neither \fBfalse\fR nor \fBnull\fR, or, if the left\-hand side produces no values other than \fBfalse\fR or \fBtrue\fR, then \fB//\fR produces all the values of its right\-hand side\.
|
The \fB//\fR operator produces all the values of its left\-hand side that are neither \fBfalse\fR nor \fBnull\fR, or, if the left\-hand side produces no values other than \fBfalse\fR or \fBnull\fR, then \fB//\fR produces all the values of its right\-hand side\.
|
||||||
.
|
.
|
||||||
.P
|
.P
|
||||||
A filter of the form \fBa // b\fR produces all the results of \fBa\fR that are not \fBfalse\fR or \fBnull\fR\. If \fBa\fR produces no results, or no results other than \fBfalse\fR or \fBnull\fR, then \fBa // b\fR produces the results of \fBb\fR\.
|
A filter of the form \fBa // b\fR produces all the results of \fBa\fR that are not \fBfalse\fR or \fBnull\fR\. If \fBa\fR produces no results, or no results other than \fBfalse\fR or \fBnull\fR, then \fBa // b\fR produces the results of \fBb\fR\.
|
||||||
|
|||||||
Reference in new issue
Block a user